[64][中等][动态规划] 最小路径和
题目描述
输入:
[
[1,3,1],
[1,5,1],
[4,2,1]
]
输出: 7
解释: 因为路径 1→3→1→1→1 的总和最小。解题思路
class Solution:
def minPathSum(self, grid: List[List[int]]) -> int:
n, m = len(grid), len(grid[0])
dp = [[0] * m for _ in range(n)]
dp[0][0] = grid[0][0]
for i in range(1, n):
dp[i][0] = dp[i - 1][0] + grid[i][0]
for j in range(1, m):
dp[0][j] = dp[0][j - 1] + grid[0][j]
for i in range(1, n):
for j in range(1, m):
dp[i][j] = min(dp[i - 1][j], dp[i][j - 1]) + grid[i][j]
return dp[-1][-1]最后更新于